MATH SOLVE

3 months ago

Q:
# The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).The slope of AC, when simplified, is equal to blank .The slope of BD, when simplified, is equal to β1 .The product of the slopes is equal to blank .Therefore, AC is perpendicular to BD.please fill in the blank spots

Accepted Solution

A:

The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).

square, all sides are equal so side = a

A(0, 0) , B(a, 0) , C(a, a), and D(0,a).

The slope of AC = (a-0)/(a-0) = a/a = 1

The slope of BD, when simplified, is equal to β1

The product of the slopes = 1(-1) = -1

Therefore, AC is perpendicular to BD.

square, all sides are equal so side = a

A(0, 0) , B(a, 0) , C(a, a), and D(0,a).

The slope of AC = (a-0)/(a-0) = a/a = 1

The slope of BD, when simplified, is equal to β1

The product of the slopes = 1(-1) = -1

Therefore, AC is perpendicular to BD.