The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).The slope of AC, when simplified, is equal to blank .The slope of BD, when simplified, is equal to −1 .The product of the slopes is equal to blank .Therefore, AC is perpendicular to BD.please fill in the blank spots
Accepted Solution
A:
The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).
square, all sides are equal so side = a A(0, 0) , B(a, 0) , C(a, a), and D(0,a).
The slope of AC = (a-0)/(a-0) = a/a = 1 The slope of BD, when simplified, is equal to −1